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  • Example

    We shall solve the system

    Stage l: An LU decomposition of the system is

    Stage 2: Set y = U1x and then solve the system L1y = b, i.e.,

    Using forward substitution, we obtain:

    Stage 3: Solve

    Back-substitution now yields:

    Thus the solution of Ax = b is:

    which may be checked, using the original equations. We turn now to the problem of finding an LU decomposition of a given square matrix A.

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